Question

A car starts from rest and accelerates at a rate of 5.75 m/s/s for a time (t1) of 6.76 seconds. The car then maintains a constant speed for a time of 7.32 seconds (t2 minus t1). Finally, the car slows down at a rate of -4.21 m/s/s. Determine the total distance traveled by the car from its starting position to its stopping position.

I already got the first (131.38) and second (284.53) values for distance traveled, how can I get the third? I tried everything I could but nothing works.

Answer 1

you know the initial speed and the deceleration

with uniform deceleration, the average speed is half of the initial speed

time = initial speed / deceleration

distance = average speed * time