Asked by Calvin
A car starts from rest and accelerate uniformely at 4m/s^2 for 6 seconds. for the next 8 sec. the driver moves with constant velocity. After this the driver applies brakes and stops the car in 10 sec. What is the total distance travelled by the car?
Answers
Answered by
Henry
V1 = a*t = 4 * 6 = 24 m/s.
d1 = 0.5a*t^2 = 0.5*4*6^2 = 72 m.
d2 = V*t = 24 * 8 = 192 m.
V = Vo + a*t = 0.
a = -Vo/t = -24/10 = -2.4 m/s^2.
V^2 = Vo^2 + 2a*d = 0.
d3 = -(Vo^2)/2a = -(24^2)/-4.8 = 120 m.
d = d1+d2+d3.
d1 = 0.5a*t^2 = 0.5*4*6^2 = 72 m.
d2 = V*t = 24 * 8 = 192 m.
V = Vo + a*t = 0.
a = -Vo/t = -24/10 = -2.4 m/s^2.
V^2 = Vo^2 + 2a*d = 0.
d3 = -(Vo^2)/2a = -(24^2)/-4.8 = 120 m.
d = d1+d2+d3.
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