Question
A car starts from rest and accelerates uniformly along a straight horizontal road at 3 metres second squeared for 4 seconds,after which it continues with a constant velocity for a further 6 seconds.CALCULATE THE MAGNITUDE OF THE MAXIMUM VELOCITY OF THE CAR, THAT IS THE VELOCITY OF THE CAR AFTER ACCELERATING FOR 4 SECONDS
Answers
V = at = 3m/s^2 * 4s = 12m/s.
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