Question

A car starts from rest and accelerates uniformly to a velocity of 8ft/s after traveling 250 ft. Find its acceleretaion.

Help me with this pleeaase.
Thank you.

Answer 1

In this situraion,
Vf = sqrt(2aX) where
Vf = the final velocity, 8 ft/s
X = the distance traveled, 250 ft
Solve for the acceleration, a, in ft/s^2.

Answer 2

i don't get it

Answer 3

What don't you get? The derivation of the first formula or how to solve it for a?

Here is how to derive the first formula.

Vf = a t
X = (1/2) a t^2

Vf^2 = a^2 t^2 = 2 a X
Vf = sqrt(2 a X)