Asked by ariana
how many real number solutions does the equation have?
-8x^2-8x-2=0
the answer is 1, but why
please and thank you
-8x^2-8x-2=0
the answer is 1, but why
please and thank you
Answers
Answered by
R_scott
divide by -2 ... 4 x^2 + 4 x + 1 = 0
factoring ... (2 x + 1)(2 x + 1) = 0
it's a perfect square
factoring ... (2 x + 1)(2 x + 1) = 0
it's a perfect square
Answered by
henry2,
The number of solutions tells you how many times the function
touches or crosses the x-axis.
h = Xv = -B/2A = 8/-16 = -1/2.
Plug -1/2 into the given Eq. and get Y = 0.
V(-1/2, 0).
The parabola touches the x-axis at the vertex only.
If the vertex was above the x-axis, we'll have 2 solutions.
touches or crosses the x-axis.
h = Xv = -B/2A = 8/-16 = -1/2.
Plug -1/2 into the given Eq. and get Y = 0.
V(-1/2, 0).
The parabola touches the x-axis at the vertex only.
If the vertex was above the x-axis, we'll have 2 solutions.
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