151 = 235t - 16t^2
16t^2 - 235t + 151 = 0
Solve using the methods you learned to solve quadratics
There will be two positive answers, one would represent the time on its way down, and the other on its path down
(According to your equation, the rocket has an initial velocity of 235 ft/s, but has no propulsion other than gravity after launch.)
h=235t-16t^2
find all values of t for which the rocket's height is 151 feet
1 answer
1 answer