Asked by ashleigh
How much water at its boiling point can be vaporized by adding 1.50 kJ of heat? ΔHvap for H2O = 40.7 kJ/mol
Answers
Answered by
DrBob222
40.7 kJ/mol x #mols = kJ
40.7 kJ/mol x #mols = 1.50 kJ.
Solve for # mols. If you want grams, convert mols to grams by
grams = mols x molar mass = ?
40.7 kJ/mol x #mols = 1.50 kJ.
Solve for # mols. If you want grams, convert mols to grams by
grams = mols x molar mass = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.