Asked by ashleigh

How much water at its boiling point can be vaporized by adding 1.50 kJ of heat? ΔHvap for H2O = 40.7 kJ/mol

Answers

Answered by DrBob222
40.7 kJ/mol x #mols = kJ
40.7 kJ/mol x #mols = 1.50 kJ.
Solve for # mols. If you want grams, convert mols to grams by
grams = mols x molar mass = ?

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