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Water is added to two containers for 16 minutes. The equations below model the ounces of water, y, in each container after x minutes. At the time after the start when the containers hold the same amount of water, how much water do they hold?
Container A: y= 16x+104
Container B: y= -2x²+40x+160
A. 360 oz.
B. 328 oz.
C. 232 oz.
D. 136 oz.
Container A: y= 16x+104
Container B: y= -2x²+40x+160
A. 360 oz.
B. 328 oz.
C. 232 oz.
D. 136 oz.
Answers
Answered by
Damon
well when is the amount in A equal to the amount in B ??
16 x + 104 = -2 x^2 + 40 x + 160
well first divide everything by 2 to make it easy
8 x + 52 = - x^2 +20 x + 80
now put everything on the left
x^2 + 8 x - 20 x + 52 - 80 = 0
or
x^2 - 12 x - 28 = 0
go here
x = -2 or x = 14
use x = 14
y = 16(14) +104 = 328 ounces
or
y = -2 * 14^2 + 40 * 14 + 160 = -392 + 560 + 160 = 328 remarkable
16 x + 104 = -2 x^2 + 40 x + 160
well first divide everything by 2 to make it easy
8 x + 52 = - x^2 +20 x + 80
now put everything on the left
x^2 + 8 x - 20 x + 52 - 80 = 0
or
x^2 - 12 x - 28 = 0
go here
x = -2 or x = 14
use x = 14
y = 16(14) +104 = 328 ounces
or
y = -2 * 14^2 + 40 * 14 + 160 = -392 + 560 + 160 = 328 remarkable
Answered by
Damon
https://www.mathsisfun.com/quadratic-equation-solver.html
sorry, forgot quad eqn link
sorry, forgot quad eqn link
Answered by
Joey
The answer is B 328
Answered by
uh
thanks:)
Answered by
jp
thanks i used 3 calculators and could not get the answer
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