Use the balanced equation to convert 24g of glucose to mol of glucose then to mol of CO2. Then use the PV=nRT equation to solve for volume.
Ps I might be wrong
The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas:
C6H12O6(aq)+6O2(g)→6CO2(g)+6H2O(l)
Calculate the volume of dry CO2 produced at body temperature (37 ∘C) and 0.990 atm when 24.0 g of glucose is consumed in this reaction.
use 3 sig figs
plz show your work
2 answers
Cody Jinks is almost right. Everything Cody writes is OK except the problem asks for DRY CO2 and since this is produced from the body it will be wet CO2; therefore, instead of using 0.990 atm for pressure use 0.990 - vapor pressure H2O at 37 C You can look up that value on the web or in vapor pressure tables in almost any chemistry book.
1 answer