Question
The hydrolysis of sucrose (C12H22O11) produces fructose and glucose (each C6H12O6). Two mechanisms are proposed:
I) Step 1: C12H22O11 --> C6H12O6 + C6H10O5 (slow)
Step 2: C6H10O5 + H2O--> C6H12O6 (fast)
II) C12H22O11 + H2O--> C6H12O6 + C6H12O6
Would these mechanisms be distinguishable in a dilute solution using kinetic data?
I) Step 1: C12H22O11 --> C6H12O6 + C6H10O5 (slow)
Step 2: C6H10O5 + H2O--> C6H12O6 (fast)
II) C12H22O11 + H2O--> C6H12O6 + C6H12O6
Would these mechanisms be distinguishable in a dilute solution using kinetic data?
Answers
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