Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A metal block of mass 5kg lies on a rough horizontal platform.If a horizontal force of 8N applied to the block through its cent...Asked by Diana princess
A metal block of mass 5kg lies on a rough horizontal platform. If a horizontal force of 8 N applied to the block through its center of mass just slides the block on the platform, then the coefficient of limiting friction between the block and the platform is: A 0.16 B 0.63 C 0.80 D 1.6 E 2.00.
Answers
Answered by
bobpursley
coefficent= friction/weight= 8/(5*9.8)= ...
Answered by
henry2,
M*g = 5*9.8 = 49 N. = Wt. of block = Normal force,
8-u*49 = 5*0.
u = coefficient of friction = 8/49 = 0.16.
8-u*49 = 5*0.
u = coefficient of friction = 8/49 = 0.16.
Answered by
muhammad
answer question which above
Answered by
Nneoma iheanyi
The answer is A: 0.16
Answered by
sanusi Umar toranka
Yes it is A.0.16
Coefficient of friction =force/mass*acceleration due to gravity. That is 8/5*10 =O.16
Coefficient of friction =force/mass*acceleration due to gravity. That is 8/5*10 =O.16
Answered by
FRIDAY
A METAL BLOCK OF MASS IS 5KG LIES
Answered by
Emmanuella
Yes it is 0.16
Answered by
Ekeng
Yes it is 0.16
Answered by
Jatau
The answer is 0.16
Answered by
Momoh abdulqahhar Oluwajuwonlo
Solution
F/mg
8/5*10=0.16
F/mg
8/5*10=0.16
Answered by
Emmaunel
Yes it is 0.16
F-uR
8-u*5*10
U-0.16
F-uR
8-u*5*10
U-0.16
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.