Asked by Emeera
A block of mass 5.53 kg lies on a frictionless horizontal surface. The block is connected by a cord passing a. over a pulley to another block of mass 2.25 kg which hangs in the air. Assume the cord to be light (massless and weightless) and unstretchable and the the pulley to have no friction and no rotational inertia.
The acceleration of gravity is 9.8 m/s^2.
Calculate the acceleration of the first block.
b. Calculate the tension in the cord.
Answer in units of N
Answer in units of m/s^2.
The acceleration of gravity is 9.8 m/s^2.
Calculate the acceleration of the first block.
b. Calculate the tension in the cord.
Answer in units of N
Answer in units of m/s^2.
Answers
Answered by
Damon
F = m g
F = 2.25 * 9.8 = 22.05 N
accelerated mass = m = 5.53 + 2.25
= 7.78kg
a = F/m = 22.05/7.78 = 2.83 m/s^2
F on top block is force in cord
F = m a = 5.53 * 2.83 = 15.7 N
F = 2.25 * 9.8 = 22.05 N
accelerated mass = m = 5.53 + 2.25
= 7.78kg
a = F/m = 22.05/7.78 = 2.83 m/s^2
F on top block is force in cord
F = m a = 5.53 * 2.83 = 15.7 N
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