Asked by desperatestudent
Me again. I just have one more question. I want to make sure I understand this question.
60 students were asked about movies they had seen during the past month. 20 of the students had seen a comedy, 15 had seen a horror movie, and 5 had seen both a comedy and a horror movie.
a) Find the probability that a randomly selected student had seen
a horror movie or a comedy (or both).
I drew my venn diagram.
I had 5 in the intersection part since 5 both saw a comedy and a horror movie. For the comedy section, I did 20-5 for 15 in the outermost circle. Then for the horror section, I did 15-5 for 10.
For the probability, would I just set it up like 15/60 (I chose 60 because that is the total) for the comedy and 10/60 for the horror?
60 students were asked about movies they had seen during the past month. 20 of the students had seen a comedy, 15 had seen a horror movie, and 5 had seen both a comedy and a horror movie.
a) Find the probability that a randomly selected student had seen
a horror movie or a comedy (or both).
I drew my venn diagram.
I had 5 in the intersection part since 5 both saw a comedy and a horror movie. For the comedy section, I did 20-5 for 15 in the outermost circle. Then for the horror section, I did 15-5 for 10.
For the probability, would I just set it up like 15/60 (I chose 60 because that is the total) for the comedy and 10/60 for the horror?
Answers
Answered by
anonymous
number( CUH) = number(C) + numbr(H) - number (C∩H)
= 20 + 15 - 5
= 30
You had 20+ 15 -15-5 =30 , probably a typo in the -15
It asked for the prob P(CUH)
= 30/60 = 1/2
= 20 + 15 - 5
= 30
You had 20+ 15 -15-5 =30 , probably a typo in the -15
It asked for the prob P(CUH)
= 30/60 = 1/2
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