desperatestudent
This page lists questions and answers that were posted by visitors named desperatestudent.
Questions
The following questions were asked by visitors named desperatestudent.
Hello, I am studying for an exam on Monday. I am stuck on these 4 practice questions. 1) 60 students were asked about movies they had seen during the past month. 20 of the students had seen a comedy, 15 had seen a horror movie and 5 had seen both a comedy...
6 years ago
Me again. I just have one more question. I want to make sure I understand this question. 60 students were asked about movies they had seen during the past month. 20 of the students had seen a comedy, 15 had seen a horror movie, and 5 had seen both a comed...
6 years ago
A student taking an examination is required to answer exactly 10 out of 15 questions. I think i'm supposed to use combination right? Order does not matter? Because it can be any choice of the 10 questions? I am usually horrible deciphering what to do but...
6 years ago
In a survey of 300 individual investors regarding subscription to the NYT, WSJ, and UST....: 122 sub to NYT 150 sub to WSJ 62 sub to UST 38 sub to NYT and WSJ 20 sub to NYT and UST 28 sub to WSJ and UST b) How many individual investors surveys subscribe t...
6 years ago
Let A and B be two events in a sample space S such that P(A) = .6 and p(B l A) =.5. Find P (A∩B). Well, I know that that should start off by finding P(A l B) which is found using the formula P(A∩B)/ P(B) but I am not given P(B) here so I don't know what t...
6 years ago
Answers
The following answers were posted by visitors named desperatestudent.
Venn diagrams stump me a bit but I know that they are more useful and quicker than the addition rule.
6 years ago
For question 2, I am only supposed to set up the venn diagram.
6 years ago
imgur.com/a/u 8bdn9g For reference to question 2 because this website doesn't allow urls.
6 years ago
without the space between u and 8
6 years ago
I just want to know if I should use the combination formula.
6 years ago
Or wait.. I might be getting the formulas mixed up. I think I must multiply P(A) by P(B l A) right?
6 years ago
For P(A∩B)?
6 years ago
0.3 that is my final answer.
6 years ago