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Box moving with velocity 3m/s stops after travelling distance of 12m.Retarding force acting on it ?
6 years ago

Answers

R_scott
with uniform acceleration (deceleration) to a stop
... the average velocity is half of the initial velocity

12 m / (1.5 m/s^2) = 8 s

acceleration = (3 m/s) / 8 s = .375 m/s^2

the retarding force is proportional to the mass of the box
... f = m a
... need the mass to find the force
6 years ago

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