Asked by Alex
A car is moving with a velocity of 16 m/s when the brakes are applied and the wheels lock (stop spinning). The car then slides to a stop in 37 m. Find the coefficient of kinetic friction between the tires and the road.
Answers
Answered by
drwls
Initial kinetic energy equals the work done against friction.
(1/2)MVo^2 = M*g*muk*X
muk = Vo^2/(2*g*X) is the kinetic friction coefficient you are looking for. You do the numbers.
X = 37 m
Vo = 16 m/s
(1/2)MVo^2 = M*g*muk*X
muk = Vo^2/(2*g*X) is the kinetic friction coefficient you are looking for. You do the numbers.
X = 37 m
Vo = 16 m/s
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