Asked by Anonymous
x^2 + y^2 -6x +8y =144
Complete the square to change the equation to standard form.
Complete the square to change the equation to standard form.
Answers
Answered by
bobpursley
x^2-6x+9 + y^2+8y+16=144+25
(x-3)^2 + (y+4)^2 = 13^2
(x-3)^2 + (y+4)^2 = 13^2
Answered by
Damon
x^2 + y^2 -6x +8y =144
x^2 - 6 x + y^2+8y = 144
x^2-6x +(6/2)^2 + y^2+8y +(8/2)^2 = 144 +3^2 + 4^2 = 169
(x-3)^2 + (y+4)^2 = 169 = 13^2
circle with center at (3,-4) and radius 13
x^2 - 6 x + y^2+8y = 144
x^2-6x +(6/2)^2 + y^2+8y +(8/2)^2 = 144 +3^2 + 4^2 = 169
(x-3)^2 + (y+4)^2 = 169 = 13^2
circle with center at (3,-4) and radius 13
Answered by
Anonymous
Contact - JuveTress
Answered by
amara
write -8x - 8y = 144 in slope intercept form
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