Asked by William
An electric train moving at 20kgh-1 accelerate to a speed of 30kgh-1 in 20s.find the distance travel in meters during the period of acceleration.
Answers
Answered by
oobleck
kg is mass, not speed.
the acceleration is (10km/hr)/(20s) = 0.5 km/hr/s
s = vt + 1/2 at^2
= 20km/hr * 20s + 0.25 km/hr/s * (20s)^2
= 400 km-s/hr + 100km-s/hr
= 500 km-s/hr
= 500km * 1000m/km * 1s/3600s = 138.9 m
Or, you could convert everything to meters and seconds to start with, but that's too mundane.
the acceleration is (10km/hr)/(20s) = 0.5 km/hr/s
s = vt + 1/2 at^2
= 20km/hr * 20s + 0.25 km/hr/s * (20s)^2
= 400 km-s/hr + 100km-s/hr
= 500 km-s/hr
= 500km * 1000m/km * 1s/3600s = 138.9 m
Or, you could convert everything to meters and seconds to start with, but that's too mundane.
Answered by
DrBob222
Does Kgh-1 mean kg/hr. Do you mean km/h?
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