Question
An electric train leaves a station starting from rest and attains a speed of 72km/hr in 10 second. It travels at that speed for 120 seconds. Then it undergoes uniform retardation for 20 seconds to come to halt at the next station calculate :
a) distance between the train stations.
b) the average velocity of train.
a) distance between the train stations.
b) the average velocity of train.
Answers
hint - it decelerates at half the rate it accelerated.
Now recall your basic equation of motion:
s(t) = vt + 1/2 at^2
and apply it to the three intervals.
Now recall your basic equation of motion:
s(t) = vt + 1/2 at^2
and apply it to the three intervals.
Ana is yes
Com
Com
Related Questions
A subway train starting from rest leaves a station with a constant acceleration. At the end of 5.24...
An electric train leaves a station starting from rest and attains a speed of 72km/hr in 10 second. T...
A train leaves a station. One hour later a second train which travels 10km/h faster than the first t...