Asked by Awwal
An electric train moving at 20kmh accelerates to a speed of 30kmh in 20 seconds.find the distance travelled in metres during the period of acceleration
Answers
Answered by
Damon
d = Vi t + (1/2) a t^2
Vi = 20 /3.6 = 5.56 m/s
V final = 30/3.6 = 8.33 m/s
oh well, I do not need the physics equation because
Vaverage = (1/2)(5.56+8.33)
= 6.94 m/s
6.94 m/s * 20 s = 139 meters
Vi = 20 /3.6 = 5.56 m/s
V final = 30/3.6 = 8.33 m/s
oh well, I do not need the physics equation because
Vaverage = (1/2)(5.56+8.33)
= 6.94 m/s
6.94 m/s * 20 s = 139 meters
Answered by
Owusu
Can't solve
Answered by
Fatmata M kamara
I need the solving of the question
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