Asked by #1
Reduce the equation to standard form, classify the surface x^2-y^2+z^2-4x-2z=0
I need step by step to the answer ((x-2)^2)/5 -(y^2)/5 +((z-1)^2)/5 =1
I need step by step to the answer ((x-2)^2)/5 -(y^2)/5 +((z-1)^2)/5 =1
Answers
Answered by
oobleck
it's just the good old complete-the-square method from Algebra 2, right?
x^2-y^2+z^2-4x-2z=0
x^2-4x - y^2 + z^2-2z = 0
x^2-4x+4 - y^2 + z^2-2z+1 = 4+1
(x-2)^2 - y^2 + (z-1)^2 = 5
Think you can manage that last step?
x^2-y^2+z^2-4x-2z=0
x^2-4x - y^2 + z^2-2z = 0
x^2-4x+4 - y^2 + z^2-2z+1 = 4+1
(x-2)^2 - y^2 + (z-1)^2 = 5
Think you can manage that last step?
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