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A spiral spring of nature 20cm,has a scale pan hanging freely in its lower end. When an object of mass 40g is placed in the pan...Asked by FBI
A spiral spring of natural length 25cm has a scale pan hanging freely in its lower end. When an object of mass 45g is placed in the pan ,its length becomes 26.80cm. When another object of mass 65g is placed in the pan, the length becomes 27.05cm. Calculate the mass of the scale pan.?
Answers
Answered by
Damon
F = k x
(45+m) = k (26.8-25) = 1.8 k
(65+m) = k(27.05 -25) = 2.05 k
(2.05 /1.8)[ (45+m) ] = 2.05 k
is
51.25 + 1.14 m = 2.05 k
65 + m = 2.05 k
--------------------------- sutract
- 13.75 + .14 m = 0
m = 98.2 grams
check my arithmetic !
(45+m) = k (26.8-25) = 1.8 k
(65+m) = k(27.05 -25) = 2.05 k
(2.05 /1.8)[ (45+m) ] = 2.05 k
is
51.25 + 1.14 m = 2.05 k
65 + m = 2.05 k
--------------------------- sutract
- 13.75 + .14 m = 0
m = 98.2 grams
check my arithmetic !
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