Asked by Hardi
A number consist of 3 digits.The middle digit is 0 and the sum of the first and last digits is 13.If the digits are reversed the number is increased by 297.Find the original number.
Answers
Answered by
Reiny
let the appearance of the number be a0b
the value of the number is 100a + b
the value of the number reversed is 100b + a
so 100b + a - (100a + b) = 297
99b - 99a = 297
11b - 11a = 33
but we also know that a+b = 13 or a = 13-b
by substitution,
11b - 11(13-b) = 33
22b = 176
b = 8 , then a = 5
finish it up.
the value of the number is 100a + b
the value of the number reversed is 100b + a
so 100b + a - (100a + b) = 297
99b - 99a = 297
11b - 11a = 33
but we also know that a+b = 13 or a = 13-b
by substitution,
11b - 11(13-b) = 33
22b = 176
b = 8 , then a = 5
finish it up.
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