A number consist of 3 digits.The middle digit is 0 and the sum of the first and last digits is 13.If the digits are reversed the number is increased by 297.Find the original number.

Answer 1

let the appearance of the number be a0b
the value of the number is 100a + b
the value of the number reversed is 100b + a

so 100b + a - (100a + b) = 297
99b - 99a = 297
11b - 11a = 33
but we also know that a+b = 13 or a = 13-b

by substitution,
11b - 11(13-b) = 33
22b = 176
b = 8 , then a = 5

finish it up.