Asked by Zobo

given that 15.00cm3 of H2SO4 was required to completely neutralise 25.00cm3 of 0.125 mole per dm3 of NaOH. calculate the molar concentration of the acid solution
Answered by oobleck
NaOH: .025L * 0.125M = 0.003125 moles
H2SO4 + 2NaOH = Na2SO4 + 2H2O
so, you will need half as many moles of H2SO4
H2SO4: 0.0015625 moles / 0.015L = 0.104 mole/L
or, 0.1M solution
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