Asked by Anonymous
If 22 mL of 5.0 M H2SO4 was spilled, what is the minimum mass of NaHCO3 that must be added to the spill to neutralize the acid?
Answers
Answered by
DrBob222
H2SO4 + 2NaHCO3 ==> Na2SO4 + 2H2O + 2CO2
mols H2SO4 = M x L = ?
mols NaHCO3 = 2xmols H2SO4
grams NaHCO3 = mols NaHCO3 x molar mass = ?
Post your work if you get stuck.
mols H2SO4 = M x L = ?
mols NaHCO3 = 2xmols H2SO4
grams NaHCO3 = mols NaHCO3 x molar mass = ?
Post your work if you get stuck.
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