Asked by Gideon
30.00cm3 Hcl acid of conc. 6.4g/dm3 neutralised 25. 00cm3 of an unknown alkali (XOH),whose conc. was 4.85gdm3 calculate,
a. the molar conc. of XOH
be. the relative atomic mass of the element X,name the element .
a. the molar conc. of XOH
be. the relative atomic mass of the element X,name the element .
Answers
Answered by
DrBob222
mols HCl = grams/molar mass = 6.4/36.5 = about 0.18 but that's an estimate.
Then mLHCl x MHCl = mLXOH x MXOH
30 x approx 0.18 = 25 mL x M XOH
M XOH = estimated 0.2
approx 0.2 mol/L contains 4.85 g in a L so
mols = grams/molar mass
0.2 = 4.85/molar mass and molar mass = estimated 23 for XOH. O is 16 and H is 1 so 23- 17 = about 6. The element closest to that is Li but an experiment like this should yield better results. Check my work. Check your numbers in the post.
Then mLHCl x MHCl = mLXOH x MXOH
30 x approx 0.18 = 25 mL x M XOH
M XOH = estimated 0.2
approx 0.2 mol/L contains 4.85 g in a L so
mols = grams/molar mass
0.2 = 4.85/molar mass and molar mass = estimated 23 for XOH. O is 16 and H is 1 so 23- 17 = about 6. The element closest to that is Li but an experiment like this should yield better results. Check my work. Check your numbers in the post.
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