Asked by Dorothy
                A machine has a velocity of 6 and is 80% efficient.what effort will be needed to lift a load of 300N with the aid of this machine?
            
            
        Answers
                    Answered by
            R_scott
            
    80% * effort = 300N / 6
    
                    Answered by
            Anonymous
            
    The solution
    
                    Answered by
            Juliet
            
    Yes
    
                    Answered by
            Victor
            
    e=M.A./V.R.=(L/E)/V.R.
e=80%
80/100=(300/E)/6. (Cross multiply)
E=30000/480
:E=65.25
Any questions send to this no. Below
08030583848
    
e=80%
80/100=(300/E)/6. (Cross multiply)
E=30000/480
:E=65.25
Any questions send to this no. Below
08030583848
                    Answered by
            Victor
            
    e=M.A./V.R.=(L/E)/V.R.
e=80%
80/100=(300/E)/6. (Cross multiply)
E=30000/480
:E=6.25
Any questions send to this no. Below
08030583848
    
e=80%
80/100=(300/E)/6. (Cross multiply)
E=30000/480
:E=6.25
Any questions send to this no. Below
08030583848
                    Answered by
            Victor
            
    E=62.5
    
                    Answered by
            Michael
            
    A machines has a velocity ration 6 and it efficiency 75%.what effort would be needed to sift load  300n with the aid of this machine
    
                    Answered by
            Spartan
            
    300N, in your brain!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    
                    Answered by
            Samuel
            
    Victor
    
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