Question

Evaluate this integral

(1+2m)^2
----------------- dm
√m

Answer 1

(2m+1)^2 = 4 m^2 + 4 m + 1
and
1 / √m = m^-.5
so you have 3 integrals
4 m^(3/2) dm + 4 m^(1/2) dm + m^(-1/2) dm
now plug and chug