Asked by A

Evaluate the integral. ∫[0,1](12/4x^2+5x+1)dx
Answered by Steve
12/(4x^2+5x+1) = 12/(4x+1)(x+1) = 16/(4x+1) - 4/(x+1)
So, now it's easy.
4log(4x+1) - 4log(x+1) = 4log (4x+1)/(x+1)
now just evaluate at 0,1 to get
4log(5/2)-4log(1/1) = 4log(5/2)
Answered by Anonymous
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