Asked by Aguson
a cube of side of 10cm and mass 0.5kg floats in a liquid without only 0.2 of its height above the liquid surface. what is the relative density of the liquid.
Answers
Answered by
henry2,
Vc = 10^3 = 1000 cm^3. = Vol. of the cube.
Dc = 500g/1000cm^3 = 0.5 g/cm^3. = Density of the cube.
Vcb = Dc/Dl * Vc = 0.8 * 1000 = 800 = Vol. of cube below surface,
0.5/Dl * 1000 = 800,
Dl = 0.625 g/cm^3 = Density of the liquid.
Dc = 500g/1000cm^3 = 0.5 g/cm^3. = Density of the cube.
Vcb = Dc/Dl * Vc = 0.8 * 1000 = 800 = Vol. of cube below surface,
0.5/Dl * 1000 = 800,
Dl = 0.625 g/cm^3 = Density of the liquid.