Asked by Zom

A square loop 10cm on a side carries a current I' = 1A, and is placed 10cm away from a long,straight wire of current I = 10A, which is in the plane of the loop. Calculate the net force on the loop (in Newtons). Is the loop attracted to or repelled from the straight wire?

Answers

Answered by Elena
i1 =10A, i2 =1A sde a=10cm=0.1 m, distance between the straight cureent and the side 12 of the loop is b=10 cm =0.1 m

Assume that the directions of the currents are following :
i1↑I ⃞ ↓i2
Points 1,2,3, and 4 are located clockwise starting from the left bottom corner of the square

Magnetic field of the current i1
at the side 12 locations is
B12 =μ₀•i1/2•π•b =4π•10⁻⁷•10/2•π•0.1 = ..
Magnetic field of the current i1 at the side 34 location is
B34 =μ₀•i1/2•π•(a+b) = 4π•10⁻⁷•10/2•π•0.2 = ..
Ampere’s force on the side 12 is
F12=i2•a•B12 =
=1•0.1• 4π•10⁻⁷•10/2•π•0.1=...
Ampere’s force on the side 34 is
F12=i2•a•B34 =
=1•0.1• 4π•10⁻⁷•10/2•π•0.2=...

F23=F41. These forces are directed in opposite directions, =>

The net force is directed to the left (to the straight current) and is
F= F12 –F34 =….
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