Asked by Anonymous
A wooden cube of side 10cm has mass 700g.What part of it remains above the water surface while floating?
Answers
Answered by
Henry
Vc = (10cm)^3 = 1000 cm^3.=Vol. of cube
Dc = 700g / 1000cm^3 = 0.7 g/cm^3. =
Density of cube.
ha = h-(Dc/Dw)*hc,
ha = 10 - (0.7/1)10 = 3 cm. = Ht. above
water.
Dc = 700g / 1000cm^3 = 0.7 g/cm^3. =
Density of cube.
ha = h-(Dc/Dw)*hc,
ha = 10 - (0.7/1)10 = 3 cm. = Ht. above
water.
Answered by
Anonymous
Thank you
Answered by
Ankan saha
Write the full forms....vc dc ha
Answered by
Prachi dingla
Not able to understand properly
Answered by
Dhairya Sharma
Thank you.