Asked by Michael

A 550-turn solenoid is 15 cm long. The current in it is 33 A. A 3.0-cm-long straight wire cuts through the center of the solenoid, along a diameter. This wire carries a 22-A current downward (and is connected by other wires that don’t concern us). What is the force on this wire assuming the solenoid’s field points due east?
Answered by bobpursley
magnetic filed is = mu*numberturns*current all that is given for the solenoid.
now that you know magnetic field B in the solenoid, then
force on the wire: currentinwire*length*B*sinTheta