A particle of mass,m =3.0kg moves with a uniform velocity ,v=(5m/s)i+(3m/s)j. At the time ,t,the particle passes through the point r=(m)i-(3m)j from the origin. Calculate the magnitude and direction of the angular momentum about the origin at time t.

Answer 1

assume you mean
R = i - 3j
and
V = 5i + 3j
L = m * R cross V
= m *
i j k
1-3 0
5 3 0
= m[ 3 k +15 k] = 18*3 k
or 54 in z (or along k) direction

K = m * [

Answer 2

It really helps but can you please simplify the expression step by step for better understanding....