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A body accelerate uniformly from rest at 2ms-2 .calculate it,s velocity after travelling 9mAsked by Lois
A body accelerates uniformly from rest at 2m/s².calculate its velocity after travelling 9m
Answers
Answered by
oobleck
v = at
plug in your numbers
think about it. every second, the velocity increases by 2 m/s.
plug in your numbers
think about it. every second, the velocity increases by 2 m/s.
Answered by
henry2,
V^2 = Vo^2 + 2a*d = 0 + 4*9 = 36,
V = ___m/s.
V = ___m/s.
Answered by
clara
I don't know tell me
Answered by
4TheLoveOfPhysics
vi = 0 m/s,
Δd = 9 m,
a = 2 m/s²,
vf = ?
vf² = vi² + 2aΔd
vf = sqrt(vi² + 2aΔd)
vf = sqrt[0² + 2(2)(9)]
vf = sqrt[36]
∴vf = 6 m/s
Δd = 9 m,
a = 2 m/s²,
vf = ?
vf² = vi² + 2aΔd
vf = sqrt(vi² + 2aΔd)
vf = sqrt[0² + 2(2)(9)]
vf = sqrt[36]
∴vf = 6 m/s
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