Asked by Josh
A body accelerates uniformly from rest and covers a distance of 180m in 6s. Calculate the magnitude of its acceleration.
. solution
S=ut+1/2at^2
180=0x6+1/2xax6^2
180=0+a/2x6^2
180-0=36a/2
180=36a/2
180x2=36a
360=36a
360/36=36a/36
10ms^-2=a
acceleration is 10ms^-2
. solution
S=ut+1/2at^2
180=0x6+1/2xax6^2
180=0+a/2x6^2
180-0=36a/2
180=36a/2
180x2=36a
360=36a
360/36=36a/36
10ms^-2=a
acceleration is 10ms^-2
Answers
Answered by
Steve
looks good, but I'd have gone from
180 = 36a/2
to
180 = 18a
180 = 36a/2
to
180 = 18a
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.