Question

A body accelerates uniformly from rest and covers a distance of 180m in 6s. Calculate the magnitude of its acceleration.
. solution
S=ut+1/2at^2
180=0x6+1/2xax6^2
180=0+a/2x6^2
180-0=36a/2
180=36a/2
180x2=36a
360=36a
360/36=36a/36
10ms^-2=a
acceleration is 10ms^-2

Answer 1

looks good, but I'd have gone from

180 = 36a/2
to
180 = 18a