Question
A car accelerates uniformly from rest to a speed of 64.5 km/h (17.9 m/s) in 10 s. Find the distance the car travels during this time.
Answers
Damon
easy way:
average speed = 17.9/2
distance = 179/2 meters
average speed = 17.9/2
distance = 179/2 meters
Damon
Hard way:
v = Vi + a t
17.9 = 0 + a(10)
a = 1.79
x = Xi + Vi t + (1/2) a t^2
x-Xi = distance = 0 (10 + (1/2)(1.79) (100)
=179/2
v = Vi + a t
17.9 = 0 + a(10)
a = 1.79
x = Xi + Vi t + (1/2) a t^2
x-Xi = distance = 0 (10 + (1/2)(1.79) (100)
=179/2