Asked by Anonymous
A car accelerates uniformly from rest at a. After a certain time, its acceleration becomes -a. It continues to travel and stops finally. If the total displacement of the car is L, what is the total time of travel?
The answer is (4L/a)^(1/2). But why??
The answer is (4L/a)^(1/2). But why??
Answers
Answered by
Damon
distance accelerating = (1/2)at^2
same distance de-accelerating
so L = a t^2
t = (L/a)^(1/2)
I do not agree with the 4
same distance de-accelerating
so L = a t^2
t = (L/a)^(1/2)
I do not agree with the 4