Asked by Chris
How would you be able to determine the asymptotes for this particular problem? Please help me with this
f(x) = 1/[1+2^(1/x)]
f(x) = 1/[1+2^(1/x)]
Answers
Answered by
Damon
if x is huge negative you have 1/[ 1+ 2^-tiny) = 1/[ 1 + 1/2^0]
but we all know 2^0 is 1 so it is 1 /[1+1] or 1/2
if x = 0you have 1/ 2^huge or zero
if x is huge positive you have 1/2 again
but we all know 2^0 is 1 so it is 1 /[1+1] or 1/2
if x = 0you have 1/ 2^huge or zero
if x is huge positive you have 1/2 again
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