Asked by Aneesh

A bullet of 0.06kg travelling at 120m/s penetrates into a fixed target and is brought to rest in 0.01s. The distance through which it penetrates is:
Answer is 60cm
Answered by R_Scott
average velocity = (initial + final) / 2 = (120 + 0) / 2 = 60 m/s

distance = velocity * time = 60 m/s * 0.01 s
Answered by vickky
Tnx a lot
I am grateful
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