(a) The bullet takes t = 120/250 = 0.48 s to reach the deer. How far will it fall in that time? About 2.26 m.
bullet fall distance = (1/2) g t^2
(b)Aim above the deer an angle A such that V*sinA*t = (g/2) t^2
sin A = (g/2)*t/V = 0.009408
A = 0.54 degrees
A hunter aims directly at a target on the same level of 120m away.
a.) If the bullet leaves the gun at a speed of 250m/s, by how much will it miss the target?
b.) At what angle should the gun be aimed so the target will be hit?
1 answer
2 answers