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Asked by Sean

sigma from n=1 to infinity 5n^6/((n^9)+6) conv or div
6 years ago

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Answered by oobleck
well, as n gets big, (5n^6)/(n^9+6) -> 5/n^3 which is less that 1/n^2
so, what do you think?
6 years ago
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sigma from n=1 to infinity 5n^6/((n^9)+6) conv or div

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