Ask a New Question

Asked by i

What is the value of *sigma sum sign* n=0 to 40 (i^n*cos (45 + 90n)°?
2 years ago

Answers

Answered by oobleck
39
∑ i^n cos(45+90n)°
n=0
= 1 cos45° + i cos135° - 1 cos225° - i cos 315° + ...
= cos45° - i cos45° + cos45° - i cos45°
... repeated for 10 cycles
= 0
so the sum for n = 1..40 is just cos45° = 1/√2
2 years ago

Related Questions

H(o): u=10 H(o): u>10 (sigma)=2 n=25 In your research, you will fail to reject the null hypoth... Sigma x-x³/x³ dx Let sigma=1 and consider the special case of only two observations (n=2). Write down a formula for t... Let \sigma =1 and consider the special case of only two observations (n=2). Write down a formula for... Given that; Sigma*x = 52; n = 8; y = 225; Sigma*xy = 1335; Sigma * x ^ 2 = 380; Sigma * y ^ 2 = 7007... Given mu = 5 and sigma = 0.5 find the probability that a random variable, is between 3.6 and 6.1 Can I be your sigma? what the sigma am i sigma
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use