Asked by cao
please show steps. A small town has 4000 inhabitants. At 8 AM, 320 people have heard a rumor. By noon half the town has heard it. At what time will 90% of the population have heard the rumor? (Round the answer to one decimal place.
Use this equation to solve, y=yo/((1-yo)e^-kt +yo)
Use this equation to solve, y=yo/((1-yo)e^-kt +yo)
Answers
Answered by
oobleck
I don't see any differential equation. This is just logistical growth. And, you left out a scale factor. The general equation is
y = (Ly<sub><sub>0</sub></sub>)/(y<sub><sub>0</sub></sub>+(L-y<sub><sub>0</sub></sub>)e^(-kt))
Now just plug in your y<sub><sub>0</sub></sub> and you get
y = 4000L/(4000+(L-4000)e^(-kt))
Now just plug in your given points:
4000L/(4000+(L-4000)e^(-8k)) = 320
4000L/(4000+(L-4000)e^(-12k)) = 2000
a quick google search will provide you with the actual differential equation.
y = (Ly<sub><sub>0</sub></sub>)/(y<sub><sub>0</sub></sub>+(L-y<sub><sub>0</sub></sub>)e^(-kt))
Now just plug in your y<sub><sub>0</sub></sub> and you get
y = 4000L/(4000+(L-4000)e^(-kt))
Now just plug in your given points:
4000L/(4000+(L-4000)e^(-8k)) = 320
4000L/(4000+(L-4000)e^(-12k)) = 2000
a quick google search will provide you with the actual differential equation.
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