Asked by Anonymous
                Could someone show me the steps to separating the variables in the following differential equation:
dy/dx = (2x+1) / (y+1)? I keep messing it up.
            
        dy/dx = (2x+1) / (y+1)? I keep messing it up.
Answers
                    Answered by
            MathMate
            
    To separate:
dy/dx = (2x+1) / (y+1)
Cross multiply:
(y+1)dy = (2x+1)dx
To solve, integrate both sides
(y^2/2+y) = (x^2+x)+C
where C is an integration constant
    
dy/dx = (2x+1) / (y+1)
Cross multiply:
(y+1)dy = (2x+1)dx
To solve, integrate both sides
(y^2/2+y) = (x^2+x)+C
where C is an integration constant
                    Answered by
            Anonymous
            
    Thank you! How would I isolate y by itself to make this a y= expression?
    
                    Answered by
            MathMate
            
    This would be more messy if you are looking for an <i>explicit</i> solution.
You would solve for y as a quadratic equation, and verify that all solutions obtained from the equation are actual solutions.
Most of the time, an implicit solution (where y occurs in more than one term or embedded as a function) is acceptable.
    
You would solve for y as a quadratic equation, and verify that all solutions obtained from the equation are actual solutions.
Most of the time, an implicit solution (where y occurs in more than one term or embedded as a function) is acceptable.
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