Asked by mssailormouth
A rock dropped from a bridge takes 3.21 seconds to hit the water. How high is the bridge in meters?
I need to find Vsub0 to be able to calculate h....but how do I get Vsub0???
I need to find Vsub0 to be able to calculate h....but how do I get Vsub0???
Answers
Answered by
mssailormouth
is it -9.80 x 3.21= -31.458 is Vsub0??
Answered by
mssailormouth
h=151.47m??
Answered by
Damon
the initial speed is zero. It was dropped, not thrown.
Answered by
mssailormouth
accck ok so
1/2(9.80)(3.21)^2= 50.5 m
1/2(9.80)(3.21)^2= 50.5 m
Answered by
Damon
(1/2)(9.81)(3.21)^2 = 50.5 meters
Answered by
mssailormouth
I'm learning slowly but surely!
Answered by
Damon
more formally
h = Hi + Vi t - 4.9 t^2
0 = Hi + 0 - 4.9 t^2
Hi = 4.9 *3.21^2 = 50.5
h = Hi + Vi t - 4.9 t^2
0 = Hi + 0 - 4.9 t^2
Hi = 4.9 *3.21^2 = 50.5
Answered by
Damon
yes, good
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.