Asked by tasha-please help
A rock is dropped from bridge to the water below. It take 2.4s to hit water fid the final speed of the rock when it hits the water. How high is the bridge above water
Answers
Answered by
Henry
1. Vf = Vo + gt,
Vf = 0 + 9.8*2.4 = 23.52 m/s.
2. h = Vo*t + 0.5g*t^2,
h = 0 + 4.9*(2.4)^2 = 28.22 m.
Vf = 0 + 9.8*2.4 = 23.52 m/s.
2. h = Vo*t + 0.5g*t^2,
h = 0 + 4.9*(2.4)^2 = 28.22 m.
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