Question

A car traveling at 22.0 m/s accelerates for 2.37 seconds at a rate of 2.25 m/s2. How far will it travel in meters during this time?

(22.0)(2.37) +1/2(2.25)(2.37)= answer 58.5m right?

Answer 1

t^2 !!!!!! t times t

Answer 2

I did calc t^2 didn't write it though

d=Vsub0t +1/2at^2

Answer 3

d = Vi t + (1/2) a t^2
(22.0)(2.37) +1/2(2.25)(2.37)^2 = 52.14 + 6.32 = 58.5
so I agree with your calculator but not your formula :)