Asked by torrance
A car is traveling at 33.0 m/s when the driver uses the brakes to slow down to 29.0 m/s in 2.50 seconds. How many meters will it travel during that time
Answers
Answered by
Damon
a = (29.0 - 33.0)/2.50 = - 1.60 m/s^2
d = Vi t + (1/2)a t^2
d = 33.0(2.50) - 0.800(2.50)^2
d = Vi t + (1/2)a t^2
d = 33.0(2.50) - 0.800(2.50)^2