Question
A car is traveling at 60.6 mph on a horizontal highway. The acceleration of gravity is 9.8 m/s2. If the coefficient of friction between road and tires on a rainy day is 0.056, what is the minimum distance in which the car will stop? Answer in units of m. m = 60-kg.
Answers
Elena
ΔKE= W(fr)
ΔKE= m•v²/2
W(fr) = μ•m•g•s
m•v²/2=μ•m•g•s
s= v²/2 μ•g
ΔKE= m•v²/2
W(fr) = μ•m•g•s
m•v²/2=μ•m•g•s
s= v²/2 μ•g